Grade+11+block+3+objective+16

To do objective 16 actually quite easy During 1991, 130 000 people visited Rave Amusement Park. During 1997 the number had grown to 498 000. Write an exponential growth function that models this data: a) F(t)= 368 000e^0.224t b)F(t)=368 000e^0.214t c) f(t)=130 000e^0.224t d) f(t)=130 000e^0.214t

To do this question you have to enter it into your Stat plot. To do that push stat enter, enter then in L1 enter 1 then 6 just below it. In L2 put in the number of people of the 2 different years. Then push graph then zoom 9 that will give you the best picture. After that push Y= and enter the choices. The answer will go through the 2 dots on the screen. The answer is c.

Write a exponential function to model the situation. Determine what each variable represents. A price of $160 increases 9% each month. a)p(x)= 160(1.09)^x; p is the total price, and x is the number of months b) p(x)= 160(1.09)^x; x is the total price, and p is the number of months C) p(x)= 160(1.09)x; p is the total price, and x is the number of months D) p(x)= 160(1.09) x; x is the total price, and p is the number of months

To do this question you need to understand what your trying to get is the total so on the p(x) side should be the total price while. And the other side you have to ^ it because if you don’t you get you get a really big number. So the answer is A.

The intensity of light visible underneath the surface of a certain pond decreases by 4% for each metre below the surface. Write an exponential function that models the intensity of light at any depth, d, below the surface. Let Io represent the surface intensity and I(d)represent the intensity at d metres. a) I(d)=Io(0.96)^d b) I(d)=Io(0.04)^d C) I(d)=Io(0.96)^d-1 d)I(d)=Io(0.04)^d-1

To do this question you have to understand that every meter you go down light drops 4% or 0.04. Seeing that Io represents surface intensity and seeing that light at surface would be 100% and after 1 meter it would be 96% or 0.96. Also you can't go down in depth -1 so the answer would be a.