31-Writing+Linear+Equations+in+Standard+Form

Writing Standard form in y=mx+b Which is the same as saying y=(slope)x+(y-intercept) The first question I will help you solve is: 2x-3y+6=0 First you need to get "3y" by itself on one side, to do this we must find the slope and y-intercept Slope=-A/B y-intercept=-C/B So our "A" value is 2 and our "B" value is -3 and our "C" value is 6. then we just plug in the numbers into the formula to get: -2/-3 which is 0.666666667(which is the same as 2/3) this is your slope, and -6/-3 reduces to 2 which is your y-intercept. Now the tricky part to put that into a y=mx+b y=(slope)x+(y-intercept) so you would go: y=(2/3)x+2 So now you have that question solved. On to another. 4x-5y+2=0 so our slope equation is -4/-5 and our y-intercept equation is -2/-5 So now solve for slope(m) and y-intercept(b) m=0.8 or 4/5 b=0.4 or 2/5 Now to plug it into our equation y=mx+b y=(slope)x+(y-intercept) y=(4/5)x+0.4 For slope it is usually described as a fraction, and for y-intercept it can be described as a fraction or a decimal. It is really easy onece you figure it out.

http://www.themathpage.com/alg/slope-of-a-line.htm This is where I got the questions from and also where I got some help from.