objective+28+S3

Objective 28 is substitution method (real solutions) There is two ways to do this objective, there is pen and paper method and using graphmatica. Im going to show you how to do both of them... Here is the pen and paper method.... Question: **2x+y=60 3x+2y=104** L1= 2x+y=60 L2= 3x+2y=104


 * Step 1**: Choose the varible with a coefficient of 1, or solve for a single varible in either equation (in this case its the "y")

So it then becomes: L1= Y=(60-2x) L2= 3x+2(60-2x)=104
 * Step 2**: Use transitive property to substitude into the other eqution

So 3x+2(60-2x)=104 3x+120-4x=104 x=16
 * Step 3**: Solve for the non- chosen varible

Since 2x+y=60 and 2(16)+y=60 Since 32+y=60 y=28 x=16
 * Step 4**: SUBSTITUTE & SOLVE for the original varible

b) Look at the pic using technology
 * Step 5**: CHECK a) Substitute in mental math or calculator

x=16 and y=28

For the graphmatica method you type in you equations and press enter and it will look like the above picture...